1692: 图-最小生成树-Prim(不建议学生做)
金币值:2
定数:10
时间限制:1.000 s
内存限制:128 M
正确:2
提交:2
正确率:100.00% 命题人:
题目描述
#include "stdio.h"
#include "stdlib.h"
//#include "io.h"
#include "math.h"
#include "time.h"
#define OK 1
#define ERROR 0
#define TRUE 1
#define FALSE 0
#define MAXEDGE 20
#define MAXVEX 20
#define INFINITY 65535
typedef int Status; /* Status是函数的类型,其值是函数结果状态代码,如OK等 */
typedef struct
{
int arc[MAXVEX][MAXVEX];
int numVertexes, numEdges;
}MGraph;
void CreateMGraph(MGraph *G)/* 构件图 */
{
int i, j;
/* printf("请输入边数和顶点数:"); */
___________
G->arc[0][1]=10;
G->arc[0][5]=11;
G->arc[1][2]=18;
G->arc[1][8]=12;
G->arc[1][6]=16;
G->arc[2][8]=8;
G->arc[2][3]=22;
G->arc[3][8]=21;
G->arc[3][6]=24;
G->arc[3][7]=16;
G->arc[3][4]=20;
G->arc[4][7]=7;
G->arc[4][5]=26;
G->arc[5][6]=17;
G->arc[6][7]=19;
for(i = 0; i < G->numVertexes; i++)
{
for(j = i; j < G->numVertexes; j++)
{
G->arc[j][i] =G->arc[i][j];
}
}
}
/* Prim算法生成最小生成树 */
void MiniSpanTree_Prim(MGraph G)
{
________
}
int main(void)
{
MGraph G;
CreateMGraph(&G);
MiniSpanTree_Prim(G);
return 0;
}
输出样例 复制
(0, 1)
(0, 5)
(1, 8)
(8, 2)
(1, 6)
(6, 7)
(7, 4)
(7, 3)